Perfect Squares
Given a positive integer n, find the least number of perfect square numbers (for example, 1, 4, 9, 16, ...
) which sum to n.
For example, given n = 12
, return 3
because 12 = 4 + 4 + 4
; given n = 13
, return 2
because 13 = 4 + 9
.
Solution:
public class Solution {
public int numSquares(int n) {
// dp(i) represents the least number of PS which sum to i
int[] dp = new int[n + 1];
Arrays.fill(dp, Integer.MAX_VALUE);
dp[0] = 0;
for (int i = 0; i <= n; i++) {
for (int j = 1; i + j * j <= n; j++) {
dp[i + j * j] = Math.min(dp[i + j * j], dp[i] + 1);
}
}
return dp[n];
}
}